Recent content by ElizaSells

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    Expected Value of Insurance Payment

    Hi everyone, it's me again... Here is my current struggle and what I've done. First, i found the expected value of the amount of damage which is ($1,410 + $284)/2 because it is uniform. This is $847. There is a $532 deductible, so the expected payment is $847-$532 = $315. The problem is this...
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    Die With Multiple Same Sides

    Ah yes, I know the random variable is the sum, I’ve mapped out all the ways we can get each sum. I’m just not sure (for example) if the first 2 on dice A paired with any of the numbers on dice b is different from the second 2 on dice a paired with any number on dice b. I understand the problem...
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    Die With Multiple Same Sides

    Is it just 4x 6 instead of 6x6 you think?
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    Die With Multiple Same Sides

    There are 36 possible combinations of rolls when rolling two regular die. 6^2. I’m not sure if I’m this case I should do 6^2 or something else, since Dice a and b are different
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    Word Problem - Student Who Misbubbles Exam

    What I have done so far: If the student was expected to make a 75%, we basically expected he would get 15 of the 20 questions correct. Now that he has misbubbled his answers, we expect those 15 he should've gotten right to now be wrong. For the remaining questions he now has a 1/10 chance of...
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    Die With Multiple Same Sides

    Hi everyone - see my problem below. With a regular die I know my denominator is 36 for each probability. What I'm wondering here is if that changes since multiple sides of the die have the same number... Right now I have the probability of a sum of 2 is 1/36, a sum of 3 as 2/36, sum of 4 as...
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    Var (X) vs Var (X^2)

    Thanks Dason. I really appreciate your help.
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    Var (X) vs Var (X^2)

    Do you think this would change if it indicated the variance was less than one instead of greater than one? Im trying to determine if that had any effect on the problem...
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    Var (X) vs Var (X^2)

    Ah! Ok I just did a RV that can only take 1 and -1, with a 50% probability of either value. Var(x) is 1 and Var(X^2) is 0. So it does depend, we can't always say the variance of X^2 is larger than the variance of X. Thank you so much!!
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    Var (X) vs Var (X^2)

    No, it doesn't specify. I tried doing it with negative values. I did the following: X can take values from -3 to 2, with probabilities as follows (.2, .1, .4, .1, .1, .1) I found the Variance of X to be 2.29 and the variance of X^2 to be 10.29. Am I missing something?
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    Var (X) vs Var (X^2)

    Hi all - first post. I was hoping for help with the following problem: Let X be a discrete random variable and suppose Var(X)>1. How do Var(X) Var(X^2) compare? One of the answers is "not enough information to solve" which is what I'm leaning towards...I can find plenty of examples where...