My solution as per

**Binomial Distribution**:-

Probability of success(p)=1/10.

Probability of failure(q)=9/10.

Number of observations(n)=12.

P(X>=1)=

**nCx*P^x*(Q)^n-x**

=1-P(X=0).

=1-[12C0*(1/10)^0*(9/10)^12-0].

= 0.97176

=1-P(X=0).

=1-[12C0*(1/10)^0*(9/10)^12-0].

= 0.97176

**My solution as per**

**Poisson distribution:**-Mean Number of acceptances=1/10

Number of observations=12

P(X>=1)=

**1-P(X=0)**

**=1-[(****e^-m)*m^x]/x!]**

**=[(e^-1/10)*1/10^0]/0!**

**=0.964****(**

*so according to above example , probability of me getting accepted in atleast one business*school is 96%, is it really true,because i have onlu 10 % chance of getting accepted when i apply to only 1 school, plz explain any mistakes)