Hello all. I'm working on the following question:
Fifteen percent of the items produced by a machine are defective. Out of 15 items chosen at random,
a)what is the probability that exactly 3 items will be non-defective?
Now this is a binomial distribution but; pn = 85/100 (15) = 12.75 and qn = 15/100 (15) = 2.25 (right?)
With qn being so low this isn't suitable for normal approximation and so the binomial distribution can't work here right? (I tried calculating it and realized z scores seemed much too high)
So can I use the Poisson distribution for this problem? And if I do, do I have to calculate upper and lower limits (3.5 & 2.5 respectively) and then subtract one from the other like I would for the binomial distribution, or will I just use one X value of 3 for the equation?
I haven't been able to find much help online about using the Poisson distribution for just two outcomes.
Let me know if I'm missing something here.
Really appreciate any help or advice!
Fifteen percent of the items produced by a machine are defective. Out of 15 items chosen at random,
a)what is the probability that exactly 3 items will be non-defective?
Now this is a binomial distribution but; pn = 85/100 (15) = 12.75 and qn = 15/100 (15) = 2.25 (right?)
With qn being so low this isn't suitable for normal approximation and so the binomial distribution can't work here right? (I tried calculating it and realized z scores seemed much too high)
So can I use the Poisson distribution for this problem? And if I do, do I have to calculate upper and lower limits (3.5 & 2.5 respectively) and then subtract one from the other like I would for the binomial distribution, or will I just use one X value of 3 for the equation?
I haven't been able to find much help online about using the Poisson distribution for just two outcomes.
Let me know if I'm missing something here.
Really appreciate any help or advice!