Empty cell when importing csv file


We are going to import a csv format file to R system.

For example,

a <- read.csv(file="c:\\order4.csv", header=TRUE, sep=",");

are used to import. However the new file a in R is list, instead of matrix which is easily used for us.

1) What is the *** command to convert from list to matrix?

2) The a file has lots of empty cell (NA ot Null). Can we put zero ("0") to all empty cell in R?

Thanks in advance.

PS) Possible candidate answer is sapply(a, is.na) and read.csv(***, na.strings("", "NA")) or something like that.

PS) For further illustration, I can make realistic example to explain situation.


Probably A Mammal
1. Don't need to indicate sep="," when you're using read.csv. The point of read.csv is a convenience version of read.table that presets some parameters, like sep = ","
2. Your data imports as a data.frame. When you do typeof it comes back as list because data frames are, behind the scenes, a type of list: a list of column vectors of equal length.
3. If you want to post-process na values into 0s that's a simple operation

x <- read.csv(...)
x$mycolumn[is.na(x$mycolumn)] <- 0
But if you want to blanket this across the entire data frame (list), you can use lapply in a tricky way

replace_na <- function(x, value=0) 
    x[is.na(x)] <- value
x[] <- lapply(x, replace_na)
Here replace_na takes in a vector and replaces it with a value (default to 0). With data frames, since they're column vectors in a list, lapply will loop across all its columns. We're replacing the contents of x (x[]) with the resultant vectors.

Caveat: this doesn't work with factors, so I'd recommend including the stringsAsFactor = FALSE parameter in your read.csv statement to avoid them.

Alternatively, you can select which columns to replace

x[, c(1, 3, 5)] <- lapply(x[, c(1, 3, 5)], replace_na)