Finding Z-score for 62% central distribution.


I have a homework problem, where I need to find the Z-score, that contain the central 62% of the normal distribution. I have no other information.

Any hints of how to find this, I am at a loss?
And where does that lead you?
Ah, I think i see it now. So i find the left tail z at 19%, which is -0,88 and to find the right tail z i look at 81%, which is 0,88.
P(x<-0,88 or x>0,88) = 0,37886. So this is the z-score, ± 0,88? Since 1-0,38 = 0,62 (62%).
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