# How Do I present Multiple Relationship of Multiple Items?

#### BenHoughton

##### New Member
Hi all, first time poster here - be gentle with me!

I'm currently analysing (in the loosest possible sense!) a whole bunch of data. This is revolving around polypharmacy of drugs.

Part of this involving seeing how many times Drug A is present with Drug B. Only it doesn't stop at B, it may go how many times Drug A is present with Drug B+C and D or B+C but no D.

In my head I can see that on the left hand side I can show all the different Drug A's (for argument sake, around 10 different 'A') with the potential Drug B,C,D,E etc across the top and then simple add a number for number of times present but I don't see how I can include anything other than single times present? Is there a way to show B+C+D without adding those combinations as separate values in the chart?

I feel like thats rambling, sorry! Stats aren't my strong point!

#### obh

##### Member
Welcome, Ben,
From my experience, there are nice people in this forum, gentle with all

I try to understand your goal, with a small example:
a: 5
ab: a=6, b=3
ac: a=7, c=9
bc: a=8, b=5

Before the "how", What do you want to show?
For example is there a meaning to show a: 18 (5+6+7) ?

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#### BenHoughton

##### New Member
Thank you for the prompt response. I don't think I explained myself very well!

Basically sometimes people are given more than one drug. Sometimes this is ok, sometimes it is against guidance. I have a whole bunch of data telling me how many times different drugs are prescribed.

What I want to show is how many times one drug is prescribed alone and then how many of the other combinations the drug is prescribed. This may be simply drug A plus drug B but it may also be drug A plus B,C,D and sometimes it might be drug A plus B and D only.

I'm not sure if there's any easy graphical way to show that?

#### obh

##### Member
So if you are interested only with the combinations, why not showing each combination (a alone is also combination) as a stack bar, or as a bar?

#### BenHoughton

##### New Member
ah that would work. Thank you for the suggestion