average should be located to minimise the fraction nonconforming. What would

the value of the fraction nonconforming be under these conditions? (data are normally distributed)

Variance = 77.92

Upper Limit = 20

Lower Limit = 0

\(minize P[ (20-\bar{x})/77.92 < Z < (0-\bar{x})/77.92 ] = minimize( P[Z> (20-\bar{x})/77.92] + P[Z < (0-\bar{x})/77.92 ]) = ...???\)