P{X-E(X)>=k(sigma)}<=1/(1+k^2)

Which describes the right-hand tail of the distribution (probability that values are above a bound).

Can someone help me prove to myself that a similar (or the same) equality exists for the left-hand tail (probability that values are below a lower bound)?

P{E(X)-X>=k(sigma)}<=???

Thanks-

Kevin

edit ... well, this is not homework. Still, any help?