NEED HELP URGENT! Probability Question

The boys need to arranged like this:


and the remaining 15 girls have to go into the 11 blank spots. The first or last blank could be left empty, but there has to be at least one girl in each of the 9 blank spots between the boys


That leaves 6 girls that can go into any of the 11 spots.

The number of different ways to distribute n indistinguishable girls into k distinguishable spots is \({{n + k - 1}\choose{k - 1}}\)

\({{6 + 11 - 1}\choose{11 - 1}} = {{16}\choose{10}} = 8008\)
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I'm guessing we're assuming that they be in a line and that it's not a circle or a square or something else...


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Do you have an actual problem or question you can post, which may help to eliminate some of the vagaries.