# Newbie Really Needing Help

#### Leper Messiah

##### New Member
I am having a problem with one of my assignments for my class, and for the life of me, I cannot solve it. Any help would be much appreciated!

Here it is:

A committee of four is to be selected from a group of 15 people. How many different committees are possible if one person is the chair, and the rest are general member?

#### JohnM

##### TS Contributor
I believe that your instructor is trying to throw you off with the "chair" and "general member" stuff.

It's simply 15C4 = 15! / (11! * 4!) = 1365

#### Leper Messiah

##### New Member
this is all on blackboard, and apparently, 1365 is not correct. I really don't think that this should be so freaking hard.

#### JohnM

##### TS Contributor
Hmmmm - you know, maybe I missed something here.

1365 is the number of "general" committees, not considering who is the "chair." If we take any one committee of 4, then there are 4 ways in which 1 of them can be the chair, and the rest are just part of the committee.

Try multiplying 1365 * 4 = 5460

#### Leper Messiah

##### New Member
My God, you were right!! Thanks a million!!!

Any way you could give me a brief step by step on how you did that in case I need it for a quiz??