Percentage Greater/Area

#1
Hello everyone,

I am having a little difficulty figuring out how to solve this question:
The average snowfall in Boston is 44 inches with a standard deviation of 17 inches, if Boston's 1996 snowfall was 33 inches, what percentage greater was the snowfall of the winter of 1997 (62 inches)?

I figured out the z-score for both, then subtracted the percentage from the z-score in 1996 from the one in 1997, but this answer appears to be incorrect according to the quiz answer...can anyone help?

Thank you so much!
-Sara
 

JohnM

TS Contributor
#2
percent increase is computed by:

(62 - 33) / 33 = .879
.879 * 100 = 87.9
= 87.9%

in general, it is "amount of change" divided by "original amount" multiplied by 100