# Please, I need help on a measurement problem using statistics

#### Maria Girisa

##### New Member

The objective would be to find a representative value per m2, ie to find a formula to calculate the value of m2, which takes into account all the characteristics the information provided by the farmers of a city. This value would be used, for example, to calculate the price of the lands of those people who could not declare exactly the plants they possessed.
The information available is:

1) In a city with 1000 farmers, farmers have declared n different types of plantations. Of the total farmers, 97% declared to plant oranges, 90% declared to plant lemons, 85% declared to plant apples and 70% declared to plant pumpkins, etc.

2) When a farmer declared that he possessed a plant, he could declare the number he had. Not everyone remembered it and stated a precise number.

Note: Of the 97% who claimed to have oranges, only 15% reported knowing the quantity. And of the 90% who claimed to have lemons, only 7% reported knowing the amount. And of the 85% who declared they own apples, only 22% reported knowing the quantity. And of the 70% who reported having pumpkins, only 3.5% reported knowing the quantity.

For those who have declared some value:
The average of the declared plants for each property was: 7 oranges, 12 lemons, 12 apples and 15 squash.

3) The value of each plante is: orangre = $15.00 ; lemon =$ 20.00, apple = $25.00 and pumpkin =$ 15.00.

4) The average size of the planted land in the city is 543 m2.

Solution Attempt:

I multiplied the percentage value of those who declared owns the plant * the declared average of quantity of the plant * the value of the plant and divided by the total in meters of the property.

Ex.
Orange = 0.97 * 7 * 15/543 = 0.1875
Lemon = 0.9 * 12 * 20/543 = 0.3978
Apple = 0.85 * 12 * 25/543 = 0.4696
Pumpkin = 0.7 * 15 * 15/543 = 0.2900

Total value of m2 = 0.1875 + 0.3978 + 0.4696 + 0.2900 = 1.3413

Please, I would like correction suggestions or other possible ways to solve the problem.