A player rolls two dice and is awarded 1 point if the same number appears on the upface of both dice. If different numbers appear, he gets no points. Let X be the number of points a player could earn in three attempts. What is the probability of X?
X {0, 1, 2, 3}
P(X) {0.579, 0.347, 0.069, 0.005}
______________________________________________________________
Dice 1
1
2
3
4
5
6
Dice 2
1
2
3
4
5
6
so the way i see it is that there is a 1/6 chance of getting one number from each die so the probability of getting two numbers the same should be 1/6 x 1/6 = 0.0277 but thats different from the answers given above and why does the X-value only go up to 0, 1, 2, and 3 where there are 6 numbers on a dice?
anyone know how to do this problem?
thanks in advance
X {0, 1, 2, 3}
P(X) {0.579, 0.347, 0.069, 0.005}
______________________________________________________________
Dice 1
1
2
3
4
5
6
Dice 2
1
2
3
4
5
6
so the way i see it is that there is a 1/6 chance of getting one number from each die so the probability of getting two numbers the same should be 1/6 x 1/6 = 0.0277 but thats different from the answers given above and why does the X-value only go up to 0, 1, 2, and 3 where there are 6 numbers on a dice?
anyone know how to do this problem?
thanks in advance