p(A and B) = p(B)*p(A)

where the p(A and B) = probability of sampling someone who follows X and Y pages two times (once when sampling for X and once for the Y) = 1200/(61000+46000) = 1200/108000 = 0.011

p(A) = probability of sampling an X follower who also follows the Y

p(B) = the probability of sampling an Y follower who also follows the X

I am going to assume that p(A) = p(B).

so we can substitute 0.011 for p(A and B) and p(A) for p(B) to get:

0.011 = p(B)*p(B)

0.011 = p(B)^2

.104 = p(B) = p(A)

So, roughly 10% of X's followers also follow Y's. Am I correct in this line of reasoning? Is there anything I am missing?