2.A darts player finds that on average he hits the bullseye 4 times out of 5. Calculate the probability that in a random sample of 4 shots, he will miss the bullseye at least 3 times

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2.A darts player finds that on average he hits the bullseye 4 times out of 5. Calculate the probability that in a random sample of 4 shots, he will miss the bullseye at least 3 times

Can you show what you did for the second question, the answer you got, and what you think the correct answer is?

p=probability of success=0.2

q=probability of failure=0.8

x=no of successes in n trials=3 or 4

P(x<=4, but>=3)=P(x=4)+P(x=3)

=(4C4 x (0.2)^4 x (0.8)^0)+(4C3 x (0.2)^3 x (0.8)^1))

=(0.1667x0.0016x1)+(2x0.008x0.8)

=0.013

The correct answer is 0.0272

All of your work for that is correct except for one thing. In both cases where your calculating using the "choose" function you're getting it wrong.

4C4 is 1 and 4C3 is 4. I'm not sure how you're getting your answers of 1/6 and 2 but that seems to be your issue with that problem.

4C4 is 1 and 4C3 is 4. I'm not sure how you're getting your answers of 1/6 and 2 but that seems to be your issue with that problem.