Assume that there are 13 spaces and each can have 1 of 36 independent alphanumerics. There are 36^13 possibilities = 1.17x10^20 altogether.

We are considering a 6 letter message, and ignore the very rare case of that message appearing twice.

There are 8 possible starting positions. For each there we have one message and 7 odd letters, so there are 8x36^7 cases where the message appears.

So, p = 8*x36^7/(1.17x10^20) = 3.68x10^-9. With 16x10^6 codes sent out there is about a 6% chance of this particular six letter message appearing.

With many possible messages to spark attention, it is quite likely that one will be spelled out.