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  1. S

    Chance without replacement

    I'm ready to try this Going back to this scenario, 2 good balls I want out of 4 so the chance to not draw either on first turn = (3-n)/(5-n) = 2/4 = 50%. So On average I only need to draw 1 ball to get either or? This is part I'm stuck on due to only needing 2 rs and 3 bs how should I handle...
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    Chance without replacement

    Is this supposed to be (98-n)/(100-n)? EDIT: I"m sorry, just matters that first term would be 98/100 depending on how you start n I apologize i don't know how to insert symbols and hope math lingo is right Does this work? For average for drawing the one remaining ball would be summation of (1...
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    Chance without replacement

    My main issue is how do you know when its better to switch to new bag or when to keep going until you get next ball. For example I assume if I drew either red or blue on first marble draw then I should switch right? rather then continue digging through bag for a 1 in 98? After you successfully...
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    Hi, I replied to your post in the thread I started...

    Hi, I replied to your post in the thread I started http://www.talkstats.com/threads/chance-without-replacement.74587/#post-217990
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    Chance without replacement

    that's the part that's most confusing for me, I'm not sure how to set up the probability for the average number of pulls from a finite bag needed to draw 1 of 2 variables. If it was just one marble from a bag of 4 i wanted, [1+2 +3+4]/4 = 2.5 draws? on average to one desired marble. But when its...
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    Chance without replacement

    Bumping due to first attempt at problem. Average number of pulls to draw either r or b from 1 bag is 34 pulls. Therefore, assuming on average if 34 pulls then 66 balls remaining with one of desired it makes more sense on average to continue pulling through same bag for last marble for average...
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    Chance without replacement

    I have a statistics I'm not sure how to set up. I have a bag of marbles 98 Black, 1 Red, and 1 Blue. I pull one marble out at a time without replacement At anytime you have option to throw out current bag and start a new bag with original 98 Black, 1 Red, 1 Blue count. I want to represent...