- Thread starter Ferra
- Start date
- Tags kernel density nhpp

I'd like to calculate the overall failure intensity of the system (The system will fail when the density of defects in both layers reach a certain limit).

follows NHPP which depends on the previous history (conditional NHPP)

Given the individual failure limit

\( \tau_1 = \min\{t: N_1(t) \geq n_1\} \)

\( \tau_2 = \min\{t: N_2(t) \geq n_2\} \)

And you want to find the distribution the overall system failure time, which is given by

\( \tau = \max\{\tau_1, \tau_2\} \)

Is it what you want?