Standardized GPA: p-value < .0001, B estimate = 1.7154, odds ratio = 5.559

I interpret this as, with every 0.33 unit (one standard deviation) increase in GPA, the odds of succeeding in the certification exam increased by 5.559 times.

However, clients want to understand this in terms of probability. I calculated probability by:

(5.559 - 1) x 100 = 455.9 percent

I'm having trouble explaining this percentage to our client. I thought probability of success is only supposed to range from 0 to 1. Any help would be appreciated!