- Thread starter katxt
- Start date

It looks like it should be 2/3*3/4 = 1/2 but there's something funny here.

If A, B and C are evenly matched, A beats B in a two way race 1/2 of the time and A beats C in a two way race 1/2 of the time.

But the probability of A beating B and C in a three way race is not 1/2*1/2 = 1/4. It is clearly 1/3 because they are all equally likely to win.

So how about the problem in the first post?

I kind of want to change it to a dice rolling problem

But I have to agree with Dason. Other scenarios give different results.